-25x^2-15x-2=0

Solution for -25x^2-15x-2=0 equation:

-25x^2-15x-2=0

a = -25; b = -15; c = -2;
Δ = b2-4ac
Δ = -152-4·(-25)·(-2)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-5}{2*-25}=\frac{10}{-50}
=-1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+5}{2*-25}=\frac{20}{-50}
=-2/5
$